An electrical charge 2x108
is placed at the point I CI, 2,4 m !
then at the point C4, 2,00m,
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Answer:
Explanation:
potential will be 36 V ,
field will along y-axis ,
field will increase if the space between the points is filled with a dielectric ,
All of the above:
r=√(4-1)²+(2-2)²+(0-4)²,
= 5m,
V=1/4π∈ . q/r,
(9×10^9)(2×10^-8)/5,
=36 V.
Field is in the direction of r= r p- r r.
Hope it helps.
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