Question

find the ratio of kinetic and potential energy of H atom of ( n - 1 ) th orbit

Answer 1

By Bohr's theory :

K(Ze)e/r² = mv²/r

Kinetic energy = 1/2 mv² = K(Ze)(e)/2r

Potential energy = F.dr = -K(Ze)(e)/r

Ratio of K.E and P.E ={K(Ze)(e)/2r}/{-K(Ze)(e)/2r} = -1/1

= - 1 : 1

ANSWER is - 1 : 1