Question

An electrical contractor purchases a certain amount of wire, 10% o f which was stolen. after using 85% o f the remainder, he had 47 m 25 cm o f wire left. how much wire did he purchase?

Answer 1

Wire left after stolen = 0.9L
Used 85%, left 15% = 0.9Lx15%=47.25

L = 350m

Answer 2

The length of the purchased wire is 350m.

Given:

The stolen part of the wire is 10%.

The remaining part used is 85%.

The length of the wire is 47m 25cm.

To Find:

Length of purchased wire.

Solution:

Here, it is given that $10\%$ part of the wire was stolen.

now, the wire that is left after stolen $=100\%-10\%$

                                                             $=90\%$.

so, the $90\%$ is $=\frac{90}{100}$ $=0.9$.

now, we have given that $85\%$ part of the wire is used so, the part of the wire that is left is $15\%$.

here, the wire that is left after being stolen is $0.9$ .

Let's suppose that the purchased wire's length is $L$.

so now we get,

$0.9\times L\times 15\%=47.25$

now, after calculating the values given in above.

we get, $L=\frac{47.25}{0.9}\times \frac{15}{100} \\L=\frac{47.25\times 100}{0.9\times 15}\\L=\frac{4725}{13.5} \\L=350m.$

Hence, the length of the purchased wire is 350m.