An electromagnetic wave going through vacuum is described by E = E₀ sin(kx - ωt); B = B₀ sin(kx - ωt). Which of the following equations is true?(a) E₀k = B₀w(b) E₀w = B₀k(c) E₀B₀ = wk(d) None of these
Answers
Answered by
13
Answer:
A) Eok = Boω
Explanation:
Electromagnetic wave = E = E₀ sin(kx - ωt) (Given)
The relation between Eo and Bo is given by = Eo/Bo = C (1)
where C = speed of the electromagnetic wave
The relation between ω which is the angular frequency and k which is the wave number = ω/k = C (2)
Thus from equation 1 and 2 -
Eo/Bo = ω/k =c
Thus, Eok = Boω
Therefore, the equation Eok = Boω is true
Similar questions