Question

An electron accelerated from rest under a potential difference of 1125 V, then the final speed of electron is (Consider mass of electron = 9 x 10-31 kg) ​

Answer 1

Solution

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Correct option is C)

The potential difference provides the kinetic energy to the electron.

2

1

mv

2

=eV

Substitute the values in the equation:

2

1

×9×10

−31

×v

2

=1.6×10

−19

×182

v

2

=

9.1×10

−31

1.6×10

−19

×182×2

=64×10

12

v=8×10

6

m/s.

Answer 2

Answer :

Final speed of electron when accelerated under a potential difference of 1125 V is 19.8×$10^6$ m/s.

Given :

Here the given informations are

Potential difference (V) = 1125 V

Mass of electron (m) = 9.1 × $10^-^3^1$

To find :

Final velocity of electron (v)

Explanation :

If an electron is accelerated from rest under a potential difference, then the potential energy of electron

       = charge × potential difference

       = q × V

       = e × V

Gain in the kinetic energy of electron

        = ½ m$v^2$

According to conservation of energy

e × V = ½ m$v^{2}$

v =   $\sqrt{2eV/m}$

  = $\sqrt{2*1.6*10^-^1^9*1125/9.1*10^-^3^1}$

  = 19.8 × $10^6$ m/s.

Ie,The potential difference provides the kinetic energy to the electron.

To learn more questions about the topic refer to the links below:

https://brainly.in/question/7230257

https://brainly.in/question/15317150

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