Question

An electron and a proton are at a distance of 14
Angstrom. The dipole moment of this system will be​

Answer 1

Answer:

This is the answer of your question

Answer 2

Given:

An electron and a proton are at a distance of 14

Angstrom.

To find:

Dipole moment of system?

Calculation:

Let dipole moment be $\mu$:

• Let's assume charge magnitude be q, and the inter-charge separation be d

$\rm \therefore \: | \vec{\mu}| = |q| \times d$

$\rm \implies\: | \vec{\mu}| = ( 1.6 \times {10}^{ - 19} ) \times (14 \times {10}^{ - 10} )$

$\rm \implies\: | \vec{\mu}| = 22.4 \times {10}^{ - 29} \: Cm$

So, dipole moment is 22.4 × 10^(-29) Cm.

• Note that: since dipole moment is a vector, the direction of the vector will be from the negative charge towards the positive charge.

Hope It Helps.