please jaldi bata do
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KINEMATICS
A ) Time to come to rest
[ By first equation of Motion ]
★ V = U + a t
- [ as it comes to rest then v = 0 and u = 12 ]
0 = 12 + ( - 0.5 ) × t
12 = 0.5 t
★ Time ( t ) = 24 seconds ★
B ] Distance covered before coming to rest
★ STOPPING DISTANCE ( S⁰ ) = ( INITIAL VELOCITY )² / 2 × Acceleration
S = ( 12 )² / 2 × 0.5
= 144 / 1
★ Stopping distance ( s ) = 144 metres
★ Hope it helps you ★
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