Physics, asked by ultimateasher112, 1 year ago

An electron and a proton, each have de Broglie wavelength of 1.00 nm.
(i) Find the ratio of their momenta. (ii) compare the kinetic energy of the
proton with that of the electron.

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Answered by wabhitkarsmita007
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student-name Kavya Anand asked in Physics

An electron and a photon each have a wavelength of 1.00 nm. Find


(a) their momenta,


(b) the energy of the photon, and


(c) the kinetic energy of electron.


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student-name Ajay Kumar Shukla answered this

4353 helpful votes in Physics, Class XI-Science

Wavelength of an electron


= 1 × 10−9 m


Planck’s constant, h = 6.63 × 10−34 Js


(a) The momentum of an elementary particle is given by de Broglie relation:






It is clear that momentum depends only on the wavelength of the particle. Since the wavelengths of an electron and a photon are equal, both have an equal momentum.




(b) The energy of a photon is given by the relation:




Where,


Speed of light, c = 3 × 108 m/s




Therefore, the energy of the photon is 1.243 keV.


(c) The kinetic energy (K) of an electron having momentum p,is given by the relation:




Where,


m = Mass of the electron = 9.1 × 10−31 kg


p = 6.63 × 10−25 kg m s−1




Hence, the kinetic energy of the electron is 1.51 eV.




ultimateasher112: I know the answer not the steps.
ultimateasher112: The answers are
ultimateasher112: Ans (i) 1:1 (ii) 5.4 x 10 -4
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