Question

Solve using elimination method: x+3y=0, 2x-y=5

Answer 1

Hey!!!!

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We have,

(x + 3y = 0)2

and

2x - y = 5

Using Elimination Method

=> 2x + 6y = 0
2x - y = 5
(-). (+). (-)
=> 7y = -5

Thus y = -5/7

Using y in x + 3y = 0

=> x + 3(-5/7) = 0

=> x - 15/7 = 0

=> x = 15/7

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Hope this helps ✌️

Good Morning :)

Answer 2

x+3y = 0 ---------------------------------------- 1

2x-y = 5 ----------------------------------------- 2

1*2 => 2x + 6y = 0 --------------------------- 3

3-2 =>                2x + 6y = 0
                      - (  2x - y   = 5 )
                           -     +      -
                       ----------------------
                                 7y = -5
                       ----------------------
                     
                          7y = -5

                            y = -5/7

Put y in 2 => 2x - (- 5/7) = 5
                                  2x = 5-5/7
                                   2x = 35-5/7
                                     x = 30/7 * 2

                                     x = 15/7

Therefore, y = -5/7; x = 15/7

Hope this helpz :)