An electron and proton were accelerated through the same potential which one gas greater value of de broglie wavelength
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The mass of electron is less than that of proton, hence the de-broglie wavelength[ λ=h/(2mk)1/2 ]of electron will be greater than that of proton.
The mass of electron is less than that of proton, hence its momentum (mv) will be less than that of proto
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