Question

An electron at pointing A in the figure has a speed v of 1.41 E6 m/s Find (a) the magnitude and direction of the magnetic field that will cause the electron to follow the semicircular path from A to B and (b) the time
required for the electron to move from A to B​

Answer 1

b. t(AB) = πm / Bq

Explanation:

Please refer to the attached picture for the diagram.

At A, the magnetic force should be towards the right direction.

From Fleming's left hand rule, we know that magnetic field should be inwards.

r = mv/ Bq

∴B= mv / qr (r = 5cm)

b. t(AB) = T/ 2 = πm / Bq