Question

An electron has a speed 3 × 10² m/s with uncertainty 0.07%. What is the uncertainty in locating its position?

#Answer the question with proper steps#

Answer 1

• Δv= 3 x 10² x 0.07/100 == 0.21

Δx = h/4πmΔv == 6.625 x 10 power-27 /4 x 3.14 x 9.1 x 10 power -28 x 0.21

• Δv--- velocity of electron
• m-- mass of electron
• final answer after solving above == 2.78 approx

Answer 2

Answer:

Explanation:

Hope you understood