Question

An electron has a speed of 4×10^5 m/s. if it's velocity is accurate upto 10% then calculate uncertainty in position of electron?​

Answer 1

Answer:

Solution

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We have,

Speed4×10

5

Acoording to the Uncertainity principle,

Δx.mΔv=

4π

h

Δx=

4πmΔv

h

Δv=4×10

5

m/s (accurate upto 0.01%)

=

100×4×10

5

m/s

(100−0.01)

4×10

7

m/s

99.99

=24.99×10

−7

m/s

m=9.1×10

−31

kg,h=6.626×10

−34

kgm

2

/s,π=3.14

Therefore,

Δx=

4×3.14×24.99×10

−7

m/s×9.1×10

−31

kg

6.626×10

−34

kgm

2

/s

2857.11×10

−39

6.626×10

−34

kgm

2

/s

=0.0023×10

5