Question

an electron in H atom and the one in He+ ion are present in second orbits of the respective species. Both the electrons jump to ground States. Calculate the ratio of wavelength of the emmited radiation.​

Answer 1

Explanation:

11th

Chemistry

Structure of Atom

Bohr's Model for Hydrogen Atom

The energy of the electron ...

CHEMISTRY

The energy of the electron in the second and third Bohr orbits of hydrogen atom is −5.42×10

−12

erg and −2.41×10

−12

erg respectively. Calculate the wavelength of the emitted radiation when the electron drops from third to second orbit.

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ANSWER

1erg=10

−7

J⇒E

2

=5.42×10

−19

J=3.38eV

E

3

=2.41×10

−19

J=1.50eV

ΔE

3→2

=3.38−1.5=1.88eV

h×c=1242eV/nm

ΔE

3→2

=

λ

hc

=

λ

(nm)

1242

=1.88⇒λ=660.638nm