Question

An electron in hydrogen atom falls from sixth
excited state to first excited state. Total possible
lines emitted in the visible region are
(1) Zero
(2) 15
(3) 5
(4) 21​

Answer 1

Answer:

The total number of lines that emitted in the visible region is 15.

Explanation:

          To find out how many lines exactly are visible from formation during the falling off of electrons from 6th excited state to first excited state can be calculated.

Using the Probability formula $\frac{(N_{2} - N_{1}) (N_{2} - N{1} + 1)} {2}.$

Applying the values in the given formula we will get the number of spectral lines produced

$= \frac {(6-1) (6-1+1)}{2}$

$= \frac{30}{2} =15$

15 spectral lines will be formed.

Answer 2

Answer:

5

Explanation:

see the attached image and

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