Question

An electron is confined to a box of size 100 A⁰ .calculate the uncertainty in measurement of it's velocity​.plz help me with this question​

Answer 1

Answer:

5.785*10^3m

Explanation:

By de brogiles equation,

M(ΔX)(ΔV) >h/4(π)

we know that

dx = 100 *10^(-10)m

m = 9.101*10^(-31)kg

h/4(π)=5.27*10^(-35)

by putting values in de brogile equation::

ΔV=5.27*10^(-35)/9.109*10^(-31)(100*10^-10)

=(5.27)*10^4/(9.109)

=0.5785*10^4

=5.785*10^3 m

HOPE THIS MAY HELPFULL☺