Question

An electron is confined within a region of width 1.0x10^-10 m. (a) Estimate the minimum uncertainty in x - component of electron's momentum (b) if the electron has momentum with magnitude equal to the uncertainty found in part (a) what is its K.E.? Mass of electron = 9.1x10^-31kg.​

Answer 1

Explanation:

delta p * delta x >= h/4pi

since delta p should be minimum so

delta p = h/(4 pi* delta x)

delta p = 5.85631× 10^5

m * delta v = 5.85621 × 10^5

delta v = 5.85621×10^5 / 9.1× 10^-31

K.E = 1/2 m * v ^(2)

K. E = 1/2 × 9.1 × 10^-31 × 5.85621×10^5 = 2.664×10^-25 J