Question

An electron is liberated from the lower of the two large parallel metal plates separated by a distance of 20mm. The upper plate has a potential of 2400V​

Answer 1

Answer:

electice fieled

E= V/d

V = 2400Vand d =20mm =2× 10^-2m

Hence E=1 .2×10^5 ×1.6 ×10^-19N

F=1.92

10^-14 newtons

Hence acceleration a=F/m

mass of electron= 9.1 ×10^-31 kg

plug and come out success fully

Electrostatic potential engrey acquired=

e× v =1.6 ×10 ^-19 × 2400 J

kinetic energy=1/2 × m ×v^2

m=9.1 ×10 ^-31 ×v^2 =3.84 ×10 ^ -16

v=2.9 ×10 ^7 m/s

to get the time use S =ut+1/2

S =2×10 ^ -2 m

and here v= u

and a =f/m =(1 .9 × 10 ^ -14 ) / (9.1 × 10 ^ -31 ) =

2× 10^ 16 m/s ^ 2

now I hope uh will do it Ur Own

I hope it will help you regard