Question

An electron is moving around the nucleus of a hydrogen atom in a circular orbit of radius r the coulomb force between the two is

Answer 1

The Coulomb force between the electron and the nucleus is = - ke² / r³.

This can be calculated as follows:

• We know that, Coulomb force is represented as (F) = k q₁q₂ / r³

• As per the question q₁ = -e

• Charge on the nucleus is (q₂) = Ze

                                                         = e (for hydrogen Z = 1)

• Thus, F =  k( - e) e / r³

                     = - ke² / r³