Question

An electron is moving in a circular orbit of radius 5 × 10–11 m at the rate of 7.0 × 1015 revolutions per second. Calculate the magnetic field B at the centre of the orbit

Answer 1

Answer = 4.48 × 10^-11 T

Answer 2

Dear Student,

◆ Answer -

B = 14.08 Wb/m^2

● Explanation -

Current passing through the circular orbit -

I = Q/T

I = Q × f

I = 1.6×10^-19 × 7×10^15

I = 1.12×10^-3 A

Magnetic field at the centre of the orbit is -

B = μI/2R

B = (12.57×10^-7 × 1.12×10^-3) / (2 × 5×10^-11)

B = 14.08 Wb/m^2

Therefore, the magnetic field at the centre of the orbit is 14.08 T.

Thanks dear. Hope this helps you...