Question

An electron is moving with a velocity of 5 × 10 4 m/s (10 hold to the power of 4) enters into a uniform electric field and aquires a uniform acceleration of 10m/s2 in the direction of initial motion.
a) Calculate the time in which the electron would aquire a velocity double of its initial velocity.
b) How much distance would it cover in this time ?

Answer 1

Hi..
Hope this helps u!

Answer 2

Heya mate,
here is your answer,

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Initial velocity of the electron is, u = 5 × 104 m/s

Acceleration of the electron is, a = 104 m/s2

(i)

Using, v = u + at

=> 2u = u + at

=> t = u/a = (5 × 104)/( 104) = 5 s

(ii)

Distance travelled in this time is,

S = ut + ½ at2

=> S = (5 × 104) × 5 + ½ × 104 × 52

=> S = 375000 m

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