Question

An electron is placed at the eight corners of a cube of side a and an alpha partical at the centre of cube.Calculate potential energyof the system

Answer 1

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Answer...

Potential energy ,

$diagonal \: of \: cube \: = \: { \sqrt{3}a } \: \\ \\ so \: distance \: between \: electron \: and \: \\ \alpha \: particle \: = \frac{ \sqrt{3} a}{2} \\ \\ u \: = \: \frac{k \times q1 \times q2}{r} \\ \\ \: \: \: \: = \frac{k \times e \times 2e \times 2}{ \sqrt{3}a } \\ \\ \: \: \: \: = \frac{4 {e}^{2}k }{ \sqrt{3} a}$

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