An excess of agno3 is added to 100 ml of 0.01m solution of tetraaquadichloridochromium(3)chloride.The number of moles of agcl prrcipitated would be
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An excess of agno3 is added to 100 ml of 0.01m solution of ... The number of moles of agcl prrcipitated would be.
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Given, volume of solution = 100mL = 0.1L
molarity of tetraaquadichloridochromium(3)chloride, [Cr(H₂O)₄Cl₂]Cl = 0.01M
We know, Molarity = number of mole of solute/volume of solution {in L}
0.01 M = number of moles of solute /0.1
Number of moles of solute = 0.01 × 0.1 = 0.001 mol
In given complex [Cr(H₂O)₄Cl₂]Cl ,only one Cl ion are ionizable .
So, if number of moles of complex is 0.001 then, number of moles of ionizable Cl ions is 0.001 mol and hence, 0.001 mol of AgCl precipitated.
Hence, answer should be 0.001 mol.
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