Question

An electron is projected with a velocity 107 m/s at an angle theta=30 degree with horizontal, in a region of uniform electric field of 500 n/c vertically upwards. Find the maximum distance covered by an electron in vertical direction above its initial level.

Answer 1

$\mathfrak{The\:Answer\:is}$

maximum distance covered by an electron in vertical direction above its initial level

= 500*107

= 53500

$\boxed{Hope\:This\:Helps}$