Question

An electron is situated Midway between two parallel plates 0.5 CM apart was of the plates is maintained at a potential of 60 volt above the other the force on the electron is (e=1.6 x-19)

Answer 1

Answer:

$F = 1.92*10^{-15} N$

Explanation:

Given data:

Potential V=60 volts and distance between plates = 0.005 m

we know that electric field between plates is given  as

$E=\frac{V}{d}$

so

, putting all value to get electric field on electron is

$E=\frac{60}{0.005}$

E = 12000 V/m

so force on electron

F = eE

$F = 1.6\times 10^{-19}\times 12000$

$F = 1.92*10^{-15} N$

Answer 2

Answer:

1.92×10raise to power -15

Explanation:

explanation in picture