Question

An electron jumps from third orbit to first orbit. Calculate the change in angular momentum of an electron?

Answer 1

Answer:

Change will be 20.8 * 10^34

Answer 2

The change in angular momentum of an electron is $2.1\times10^-^3^4Js$.

Explanation:

The angular momentum of an electron in the n th  Bohr orbit of atom is given as

$L=\frac{nh}{2\pi}$

Here, h is the plank consatnt and its value is $6.6\times10^-^3^4Js$.

As per question, an electron jumps from  third orbit to first orbit.

so, change in angular momentum,

$\Delta L=L_3-L_1$

$\Delta L=\frac{3h}{2\pi}-\frac{h}{2\pi}$

$\Delta L=\frac{h}{\pi}$

substitute the value of h we get,

$\Delta L=\frac{6.6\times10^-^3^4}{3.14}$

$\Delta L=2.1\times10^-^3^4Js$

Thus, the change in angular momentum of an electron is $2.1\times10^-^3^4Js$.

#Learn More: angular momentum.