Question

an electron moves a distance of 6 cm when accelerated from rest by an electric field of strength 2×10000 N / C .calculate the time of travel?

Answer 1

force on electron = charge * electric field.
       F = e * E   

acceleration = force / mass
     a = F / m

s = u t + 1/2 a t²    
   as u = 0   ,  t = √(2s/a)  = √(2sm / eE)
     
t = √[ 2 * 0.06 * 9.1 * 10⁻³¹ / 1.6 * 10⁻¹⁹ * 20,000 ]  sec
   = √(3.4125 * 10⁻¹⁶) sec
    = 18.5  nano sec. 

Answer 2

Answer:0.585×10^-8 second

Explanation: