an electron moving horizontally with a velocity 4 * 10^4 m/s enters a region of uniform magnetic field of 10^-5 T acting vertically down ward, find the time it takes to come out of the region of magnetic field
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here the an electron is moving horizontally with a velocity and enters a magnetic field of 10-5 T acting vertically downward.
Now, here the time needed by the electron to come out of the magnetic field is T=2πmqB Where, m=mass of electron=9⋅1×10−31 kg q=charge of electron=1⋅6×10−19 C B=Magnetic field=10−5 T
Now the Time taken by the electron to come out of the magnetic field is ,T=2π×9⋅1×10−311⋅6×10−19×10−5=3⋅57×10−6 sec
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Now, here the time needed by the electron to come out of the magnetic field is T=2πmqB Where, m=mass of electron=9⋅1×10−31 kg q=charge of electron=1⋅6×10−19 C B=Magnetic field=10−5 T
Now the Time taken by the electron to come out of the magnetic field is ,T=2π×9⋅1×10−311⋅6×10−19×10−5=3⋅57×10−6 sec
hope it helps
if yes
then plzz mark as brainlest
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Answer:
1.78 × 10^-6 sec is the answer
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