Question

An electron moving perpendicular to a uniform magnetic field 0.500 T undergoes circular motion of radius 2.80 mm. What is the speed of electron?​

Answer 1

Answer:

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EXPLANATION:If a charge moves into a magnetic field with direction perpendicular to the field, it will follow a circular path. The magnetic force, being perpendicular to the velocity, provides the centripetal force.

Answer 2

The speed of electron is 2.46  × 10⁸ m/s.

An electron moving perpendicular to a uniform magnetic field 0.5T undergoes circular motion of radius 2.8 mm.

We have to find the speed of electron.

Concepts : If a moving electron of speed v is perpendicular to a uniform magnetic field B, it will move in a circular motion of radius r then,

Magnetic force = centripetal force

⇒ Bve = mv²/r

⇒ v = Ber/m , Here e is the charge on an electron, m is the mass of an electron.  

Given,

• B = magnetic field strength = 0.5T
• r = radius of circular path = 2.8mm = 2.8 × 10⁻³ m
• e = charge on an electron = 1.6 × 10⁻¹⁹ C
• m = mass of an electron = 9.1 × 10⁻³¹ Kg

∴ v = (0.5 × 1.6 × 10⁻¹⁹ × 2.8 × 10⁻³)/(9.1 × 10⁻³¹) = 2.46 × 10⁸ m/s

Therefore the speed of electron is 2.46  × 10⁸ m/s.

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