Question

An electron moving with a velocity of 5×10 ^14 m/s enters into a uniform electric field and acquires a uniform acceleration of 10 ^4 m/s^2 in the direction of its initial motion.
i) Calculate the time in which an electron would acquire a velocity double of its initial velocity.
ii)How much distance the electron would cover at this time?

Answer 1

Answer:

Correct option is

C

5

Initial velocity of the electron is u =5×10  

4

 m/s

Acceleration of the electron is a=10  

4

 m/s  

2

 

From first equation of motion,  

v=u+at

2u=u+at

t=u/a=(5×10  

4

)/(10  

4

)=5s

Explanation:

Answer 2

Answer:

An electron moving with a velocity of 5×10 ^14 m/s enters into a uniform electric field and acquires a uniform acceleration of 10 ^4 m/s^2 in the direction of its initial motion.

i) Calculate the time in which an electron would acquire a velocity double of its initial velocity.

ii)How much distance the electron would cover at this time?

Explanation:

answer is 5