Question

An electron moving with a velocity of 5*10^3 m/s enters into uniform electric field and acquires a uniform acceleration of 10^3 m/s^2 in direction of initial velocity. 1.Find out the time in which electron velocity will be doubled.? 2.How much distance electron would cover in this time.?

Answer 1

Answer:

i got dis question

and solved acc to iy

Answer 2

Answer:

u=5*10^3m/sec

a=10^3m/sec

v=2u=10^4m/sec

using 1st equation

v=u+at

10^4=5*10^3+10^3t

10000=5000+1000t

1000t=10000-5000=5000

t=5000/1000

5sec

using 2nd equation

s=ut+1/2at^2

s=5*10^3*5+1/2*10^3*5^2

=37.5*10^3