Question

an electron moving with a velocity of 5 10^6  m/sec  emerges  from a sheet  of paper of thickness 2.1×10^-4cm with a velocity of  2×10^6m/sec .calculate time taken by the electron to pass through the sheet  of  the paper​

Answer 1

Answer:

Initial velocity of the electron is u =5×10

4

m/s

Acceleration of the electron is a=10

4

m/s

2

From first equation of motion,

v=u+at

2u=u+at

t=u/a=(5×10

4

)/(10

4

)=5s