Question

An electron moving with a velocity of 5 × 104 m/s enters into a uniform electric field and acquires a uniform acceleration of 104 m/s2 in the direction of its initial motion. (i) Calculate the time in which the electron would acquire a velocity double of its initial velocity. (ii) How much distance the electron would cover in this time?​

Answer 1

Initial velocity of the electron is u =5×10
4
m/s
Acceleration of the electron is a=10
4
m/s
2


From first equation of motion,
v=u+at
2u=u+at
t=u/a=(5×10
4
)/(10
4
)=