An electron moving with the velocity of 5 x10^4 m/s enters into an uniform electric field and acquires a uniform acceleration of 10^4m/s in the direction of initial motion
1). Calculate the time in which the electron would acquire a velocity in its Initial velocity
2). How much distance the electron would cover in this time
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QUESTION:- An electron moving with the velocity of 5 x10^4 m/s enters into an uniform electric field and acquires a uniform acceleration of 10^4m/s in the direction of initial motion
1). Calculate the time in which the electron would acquire a velocity in its Initial velocity
2). How much distance the electron would cover in this time
ANSWER:- given
U= 5x10^4m/s
Acceleration of an electron=> a=10^4
1). V=u+at
2u=u+at
=> t=u/a
So, => (5x10^4)/(10^4)
By cutting 10^4 and 10^4 we get the ans as 5 sec
2). S=u+1/2at
=> (5x10^4)+5x1/2x10^4x10^5
=> s=357,000m
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Hope it helps
_____________________________________________________________
QUESTION:- An electron moving with the velocity of 5 x10^4 m/s enters into an uniform electric field and acquires a uniform acceleration of 10^4m/s in the direction of initial motion
1). Calculate the time in which the electron would acquire a velocity in its Initial velocity
2). How much distance the electron would cover in this time
ANSWER:- given
U= 5x10^4m/s
Acceleration of an electron=> a=10^4
1). V=u+at
2u=u+at
=> t=u/a
So, => (5x10^4)/(10^4)
By cutting 10^4 and 10^4 we get the ans as 5 sec
2). S=u+1/2at
=> (5x10^4)+5x1/2x10^4x10^5
=> s=357,000m
___________________________________________________________
Hope it helps
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