Question

An electron of mass 3.2×10-³¹kg. Is orbiting around nucleus with the speed of 2×10-⁵m/s.
Calculate momentum of electron.​

Answer 1

Explanation:

According to Heisenberg’s uncertainty principle, the product of uncertainties in position (Δx) and velocity △v≥hnπ

Question says, ‘accurate up to 0.001%’.

This indicates that the uncertainty in velocity is 0.001% of actual value, 300 m.s-1

That is, uncertainty in velocity (Δv) = 300×0.001100 = 3 x 10-3 m.s-1

Therefore, the uncertainty in position (Δx) can be calculated as follows:

△x=h4πm△u △x=6.626×10−34××1004×3.14×9.1×10−31×0.001×300 = 1.93 x 10-2m.