An electron of mass m and charge q is accelerated from rest through a potential
difference of V. Obtain the expression for the de-Broglie wavelength associated
with it
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Consider a charged particle carrying charge $q$ of mass $m$ accelerated from the rest through a potential $V$ . ... Therefore, $\lambda = \dfrac{h}{{\sqrt {2mqV} }}$ is the expression for the de-Broglie wavelength associated with a charged particle having charge and mass when it is accelerated by a potential \[V\] .
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