An electron, proton and alpha particle
kinetic energy.
The corresponding de-Broglie
th would have the following relationship:
(1) lamda(e )> lamda(p)> lamda(alpha)
(2)lamda(proton)>lamda(electron)>lamda(alpha)
(3)lamda(alpha)>lamda(electron)>lamda(proton)
(4)lamda(alpha)>lamda(proton)>lamda(electron)
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Answer:
(3)lamda(alpha)>lamda(electron)>lamda(proton)
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