Question

if 1.08g ag is deposited on the cathode when 7.5 ampere current passed through aqueous solution of agno3 for 200 seconds, then calculate efficiency​

Answer 1

Answer:

i dont no ajkajamakana

Answer 2

Answer:

Ag - + e- ----> Ag

R.A.M. of Ag = 107.87

One mole of silver ions (107.87g) require one mole of electrons.

∴ 0.7 g = 0.7/107.87 moles of electrons

= 0.00645 moles of electrons

1 mole of electrons ≡ 96500 Coulombs

∴ 0.00645 moles of electrons ≡ 0.00645 x 96500

= 622.425 Coulombs