An electron with velocity (v)is found to have a certain value of de-broglie wavelength. The velocity that the neutron should possess to have the same de-broglie wavelength is
Answers
Answer ⇒ V = 5.45 × 10⁻⁴ v.
Explanation ⇒ Let the de-broglie wavelength be λ.
We know,
λ = h/mv
where m is the mass of the electrons and v is the velocity of the electrons.
Now, If we want the same wavelength for an neutron. Then, let the velocity of the neutron should be V.
∴ λ = h/MV
∴ MV = mv [Equating both Equation.]
1.67 × 10⁻²⁷ × V = 9.1 × 10⁻³¹ × v
∴ V = 5.45 × 10⁻⁴ v.
This means that the velocity of Neutron should be 5.45 × 10⁻⁴ times the velocity of the Electrons.
Hope it helps.
Answer:
λ = h/mv
where m is the mass of the electrons and v is the velocity of the electrons.
Now, If we want the same wavelength for an neutron. Then, let the velocity of the neutron should be V.
∴ λ = h/MV
∴ MV = mv [Equating both Equation.]
1.67 × 10⁻²⁷ × V = 9.1 × 10⁻³¹ × v
∴ V = 5.45 × 10⁻⁴ v.
This means that the velocity of Neutron should be 5.45 × 10⁻⁴ times the velocity of the Electrons.