An elelectric dipole when held at 30 degree with respect to a uniform electric field of 3*10⁴ NC - 3 experience a torque of 27*10-26 NM. calculate the dipole moment of the dipole
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Answer:
18 × 10^-30C-m
Explanation:
using, torque= PEsinQ
27×10^-26= P 3×10^4 sin 30°
solving, we get
P= 18×10^-30C-m
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