Question

An element 'a' belongs to third period and 17 group of the periodic table A)write atomic no.and electronic configuration of 'a'. B)state whether 'a'is metal or non metal. C)write the nature of bond formed if 'a'reacts with another element 'b'of electronic configuration 2,8,1. D)write the formula of the compound formed.

Answer 1

a should have configuration 2,8,7
it's a non-metal
since a required 1 electron to gain noble configuration and b should lose 1 e so they will form ionic bond
ab is the formula

Answer 2

the electronic confrigation is2,8,7 it is a non metal