An element "A" burns with golden flame in air. It reacts with another element "B" Atomic number 17 to give a product "C". An aqueous solution of product "C" on electrolysis Gives a compound "D" and liberate gases "E" AND "F". Gas "E" is used in hydrogenation of vegetable oil and gas "F" is used in manufacturing of bleaching powder. Identify A, B, C, D, E and F and also write down the equations for the reactions involved.
Answers
A = Sodium (Na).
B = Chlorine (Cl2).
C = Sodium Chloride (NaCl).
D = Sodium Hydroxide (NaOH).
E = Hydrogen gas (H2↑).
F = Chlorine gas (Cl2↑).
Explanation:
An element "A = Sodium (Na)" burns with Golden flame in air (O2) to form Na2O (Sodium Oxide).
Na + O2 → Na2O.
Sodium reacts with another element "B = Chlorine (Cl - 17)" to form a product "C = NaCl (Sodium Chloride)".
Na + Cl → NaCl.
An aqueous solution of Product "C" means "Sodium Chloride (NaCl)" gives a compound "D = Sodium Hydroxide (NaOH)" and liberate gases "E = Hydrogen gas (H2↑)" and "F = Chlorine gas (Cl2↑)". Here, Aqueous solution is "Water = H2O".
2NaCl (aq) + 2H2O (l) → 2NaOH (aq) + H2↑(g) + Cl2↑(g).
Gas "E = Hydrogen gas" is used in Hydrogenation of Vegetable oil.
Vegetable oil + Hydrogen → Vanaspathi Ghee.
Gas "F = Chlorine gas" is used in the manufacture of Bleaching powder (CaOCl2).
Ca(OH)2 + Cl2 → CaOCl2 + H2O.