Question

An element ( atomic mass =60) occur in bcc structure with cell edge 300 pm what is its density

Answer 1

Density = mZ/N × a³

m = 60

Z = 2

N = 6×10²³

a = 300pm = 3×10^-8cm

a³ = 27×10^-24cm

So, density = 60×2/6×10²³×27×10^-24

= 120/1620

=0.074gm/cm³.