Question

【◆◆◆◆◆】【●●●●●】----

♣️an element crystallizes in fcc unit cell type structure . Yhe edge Length of unit cell is 150picometer . If 150gram of this element have 10 into 10 into power 23 atoms then calculate the density of the element?♣️

❎NO SPAM❎​

Answer 1

$\huge\bf\pink{\mid{\overline{\underline{Your\: Answer}}}\mid}$

d = 148.1 g

step-by-step explanation:

Given,

crystal has fcc structure

therefore,

Z(number of lattice points in one unit cell) = 4

Now,

it is given that,

a = 150 pm = 150× cm

w = mass of particles = 150 g

(in the given sample)

N = number of particles = 12 ×

(in the given sample)

d = density of element

Now,

we know that,

w/M = N/NA

where,

M = molar mass of the element

NA = Avagadro's Number

.°. w/N = M/NA

as,

d = Z×M / × NA

=> d = Z × w/ × N

=> d = 4×150/ × ×12×

=> d = 4/ × ×12

=> d = 4× / ×12

=> d = 148.1 g

Answer 2

For fcc

z=4

N=10×(10)^23N=10×(10)^23 atoms

a=150a=150 pm

=150×10^−10=150×10^−10pm

=15×10^−9=15×10^−9 cm

d=(z×M)/ (a^3×N) =(4*150)/(3375*(10)^-27 *10 *(10)^23)

=177.78 g cm^3

Please mark as brainliest if answer is correct.