Chemistry, asked by shubhanshi1818, 3 months ago

An element exist in three isotopic forms 15A, 17A and 18A. If the
percentage abundance of heaviest and lightest isotope are 40%
and 10% respectively then the average atomic mass of the
element is

Answers

Answered by yokeshps2005
1

Answer:

Average atomic mass =

100

∑% abundance × A.M

20.18=

100

20×90+x×21+(10−x)22

2018=1800+21x+220−22x

x=2020−2018

x=2%

Answered by sharmaharshika2002
1

15+17+18=50

50/3

=16.8

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