An element exist in two isotopic forms X(120) and X(122) in equal abundance.The average atomic mass of element is 121.44 .If each atom of X(120) are 10.04 times heavier than one C(12) atom then how many times each atom of X(122) is heavier than one C(12) atom?
(A) 10.04
(B) 10.4
(C) 10.2
(D) 10.167
Answers
Answered by
2
Answer:
hey... mate ans... is c 10.2
plzz mark as brainlist....XD
Answered by
6
Answer:
Mass of X¹²⁰ = 10.04 x 12 = 120.48
Average mass = X¹²⁰/2 + X¹²²/2
121.44 = 120.48/2 + X¹²²/2
∴ X¹²² = 10.2 × 12
CORRECT ANSWER IS (B) 10.4
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