Chemistry, asked by tony4981, 6 months ago

An element having FCC lattice structure has a cell edge of 120 pm . The density of the element is 6.8g/cm^3
How many atoms are present in 408 g of the element?

Answers

Answered by ashwanimahadule

0

Answer:

density=mass/volume×z/Na

Explanation:

volume (a^3), z(4),Na(6×10^23),m(408) put the values solve it and get the answer

tony4981: i want exact answer

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