An element is found in nature into isotopic forms with mass number 81 - 1 and a + 3 if the average atomic mass of the element is found to be a then the relative abundance of the heavier isotope in the nature will be
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•••> Atomic number ( X ) = 81 [ Atomic number is the number of electrons ( e- ) or protons ( p ) in an atom ]
•••> Mass number ( A ) = 81 + 24 [ Mass number is the total sum of protons and neutrons in an atom ]
Now,
a) Number of protons = 81
b) Mass number = 81 + 24 = 105
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