Question

Length of classroom is two times its height and its bredth is one and a half times its height .the cost of white washing the walls at the rate of rs.1.60 per m2 . is Rs 179.20 . find the cost of tiling the floor at the rate of RS.12.75 PER M 2.

Answer 1

Let height be x

Length=2x

Breadth =1 1x/2=3x/2

Area of 4 walls of room=179.20÷1.60=112m^2

2 (l+b)×h=112

2 (2x+3x/2)×x=112

2×7x^2/2=112

x^2=16

x=4

So height=4m

Length=8m

Breadth=6m

For tiling the floor we will find the area

Area=l×b=8×6=48m^2

Cost of tiling the floor =48×12.75=Rs.612

Required answer is Rs.612

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Answer 2

Answer:

Rs.324

Step-by-step explanation:

The main idea is to simply learn the fundamental formula for the lateral surface and total surface area of fundamental forms like cuboids whenever we encounter challenges of this nature. This will always put you on the proper path to finding the solution.

We are provided the cuboid's dimensions in this question. The cuboid's total and lateral surface areas must be determined. To determine the answer, use the cuboid's lateral surface and surface area basic formulas.

Let h be the room's height in metres.

Room length is 2 hm.

Breadth = $\frac{3}{2} hm$

Thus area = $\frac{179.20}{1.60} =112m^{2}$

$2(l+b)\times h=112$

$2(2h+\frac{3}{2}h)\times h=112\\ 2\times \frac{7}{2}\times h^{2}=112\\ h^{2}=\frac{112\times 2}{14} =16\\h=\sqrt{16}=4m$

length = $4\times 2=8m$

breadth = $\frac{3}{2}\times 4=6m$

In order to tile the floor area = $l\times b=8\times 6=48m$

Expense of tiling = $48\times 6.75= Rs.324$

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