Question

An element M has two isotopes M1 and M2.The relative atomic mass of the naturally occurring is 63.55. Calculate the percentage of each isotope?

Answer 1

Answer:

Let abundance be x.

so

$63x + 65(1 - x) = 63.55 \\ 63x + 65 - 65x = 63.55 \\ 2x = 1.45 \\ x = 0725$

So %age of M1 = 0.725 × 100 % = 72.5 %

%age of M2 = 100 - 72.5 = 27.5 %

Answer 2

Answer:

Let abundance be x.

so

\begin{gathered}63x + 65(1 - x) = 63.55 \\ 63x + 65 - 65x = 63.55 \\ 2x = 1.45 \\ x = 0725\end{gathered}

63x+65(1−x)=63.55

63x+65−65x=63.55

2x=1.45

x=0725

So %age of M1 = 0.725 × 100 % = 72.5 %

%age of M2 = 100 - 72.5 = 27.5 %